Question

pl. slove part iii in copy

Answer 1

We have to find the value of $x^4+y^4 = (x^2)^2 +(y^2)^2$

$(a+b)^2 = a^2+b^2+2ab$ is the identity for finding square of sum of two numbers.

We are given $x^2+y^2 =29 :</p><p> xy =2$

Recall the identity

$(x^2+y^2)^2 = x^4+y^4+2x^2y^2$

Substitute the known values in this equation.

$29^2=x^4+y^4+2(2)^2 </p><p>x^4+y^4 = 833$