Math, asked by swTi, 1 year ago

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Answered by Sarth45
2
x^2-4 is factor of mx^3-x^2-2x+nx

x^2-4=(x+2)(x-2)

means x+2 and x-2 are also factors of given equation

By using factors theorem

m (2)^3-(2)^2-2 (2)+n=0

8m-4-4+n=0

8m+n=8. .... (1)

m (-2)^3-(-2)^2-2 (-2)+n=0

-8m-4+4+n=0

8m-n=0. .... (2)

By adding equation 1 and 2 we get

16m=8

m=1/2

n=4

2m+n

=2 (1/2)+4

=5


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