Physics, asked by sandhyaashok91pcolil, 11 months ago

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Answered by Anonymous
4

\underline{ \boxed{ \bold{ \rm{ \purple{ \huge{Answer}}}}}} \\  \\  \red{ \star} \:  \underline{ \tt{Power}} \\  \\   \implies \sf \: P = VI = 250 \times 750 \times  {10}^{ - 3}  \\  \\  \therefore \:  \boxed{ \blue{ \rm{P = 187.5 \: Watt}}} \\  \\  \red{ \star} \:  \underline{ \tt{Resistance}} \\  \\  \implies \sf \: P =  \frac{ {V}^{2} }{R}  \\  \\  \therefore \sf \: R =  \frac{ {V}^{2} }{P}  =  \frac{ {250}^{2} }{187.5}  \\  \\  \therefore  \:  \boxed{ \rm{ \green{R = 333.33  \: \Omega}}} \\  \\  \red{ \star} \:  \underline{ \tt{Energy \: Consumed}} \\  \\  \implies \sf \: H =  {I}^{2} Rt =  {0.75}^{2}  \times 333.33 \times 14400 \\  \\  \therefore \:  \boxed{ \rm{ \orange{H = 2700 \: kJ}}}

Answered by Anonymous
1

 \huge \fcolorbox{red}{pink}{Solution :)}

Given ,

Potential difference (v) = 2.5 v

Current (I) = 750 mA or 750 × (10)^-3

Time = 4 Hr or 14400 sec

We know that , the product of potential difference and current is called electric power

 \mathtt{ \large \fbox{P = VI}}

Substitute the known values , we get

P = 2.5 × 750 × (10)^-3

P = 25 × 750 × (10)^-4

P = 18750 × (10)^-4

P = 1.8750 watt

We know that , the ratio of potential difference to the current is called resistance

 \large \mathtt{ \fbox{Resistance =  \frac{V}{I}  }}

Substitute the known values , we get

R = 2.5/0.750

R = 3.33 Ohm

We know that ,

  \large\mathtt{ \fbox{Energy = power × time }}

Substitute the known values , we get

Energy = 1.8750 × 14400

Energy = 27000 joule

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