Question

Place 1 to 10 digits such that their adjacent sum yields a different prime number every time.

Answer 1

Hey!!❤❤

YOUR QUESTION IS WRONG
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Reason for contradicting
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▶Which is the highest prime number can be obtained according to your data?

➡ That's be 10+9 = 19

so, highest prime number is 19 {A/Q}

Now, Count the prime number from 0-19

so, their is 8 prime numbers [I.e; 2,3,5,7,11,13,17 & 19].....(1)

▶Now, See how many adjacent sum will possible?

Let, take an arbitrary example - 1,2,3,4,5,6,7,8,9,10

so, here ;
1+2=3
2+3 = 5
....and so on

so, we are getting 9 results .

But, According to (1) Their only Eight possible results can happen...

It means, their must be going to happen repetation in same prime number, if we try to solve.

Hope you understand...
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staring- Amrit⭐