place a and b are 30 km apart and they are on a straight road. hamid travel from a to b on bike. at the same time Joseph start from b on bike travel towards a they meet each other after 20 minutes .if Joseph would have started from b at the same time but in the opposite direction hamid would have caught him after 3 hours. find the speed of hamid and Joseph
Answers
Answered by
67
• The relative speed of two moving bodies is the rate at which the distance between them increases or decreases.
•For two bodies moving in the same direction ,relative speed = difference of their speeds.
•For two bodies moving in opposite directions, relative speed = sum of their speeds.
SOLUTION :
Let the ' x ' km/h be the speed of Hamid and ' y ' km/h be the speed of Joseph.
GIVEN :
Total Distance from A to B = 30 km
ATQ,
i ) when both of them travel in opposite direction , then their relative speed = (x + y ) km/h
they meet in 20 minutes = 20/60 h = 1/3h
[ 1 minutes = 1/60 h]
Relative speed = Distance/ Time
x + y = 30 / ( 1/3 )
x + y = 30 ×3
x + y = 90 ………………. (1)
ii ) when both of them travel in same direction , then their relative speed = ( x - y ) km/h
they meet in 3 hr
Relative speed = Distance/Time
x - y = 30/3
x - y = 10 ………………( 2 )
On Adding eqs ( 1 ) and ( 2 ),
x + y = 90
x - y = 10
----------------
2x = 100
----------------
x = 100/2
x = 50
put x = 50 in eq ( 1 ),
x + y = 90
50 + y = 90
y = 90 - 50
y = 40
speed of the Hamid ( x) = 50 km/h
speed of the Joseph ( y) = 40 km/h
Hence , the speed of the Hamid & Joseph is 50 km/ h & 40 km/h.
HOPE THIS WILL HELP YOU...
•For two bodies moving in the same direction ,relative speed = difference of their speeds.
•For two bodies moving in opposite directions, relative speed = sum of their speeds.
SOLUTION :
Let the ' x ' km/h be the speed of Hamid and ' y ' km/h be the speed of Joseph.
GIVEN :
Total Distance from A to B = 30 km
ATQ,
i ) when both of them travel in opposite direction , then their relative speed = (x + y ) km/h
they meet in 20 minutes = 20/60 h = 1/3h
[ 1 minutes = 1/60 h]
Relative speed = Distance/ Time
x + y = 30 / ( 1/3 )
x + y = 30 ×3
x + y = 90 ………………. (1)
ii ) when both of them travel in same direction , then their relative speed = ( x - y ) km/h
they meet in 3 hr
Relative speed = Distance/Time
x - y = 30/3
x - y = 10 ………………( 2 )
On Adding eqs ( 1 ) and ( 2 ),
x + y = 90
x - y = 10
----------------
2x = 100
----------------
x = 100/2
x = 50
put x = 50 in eq ( 1 ),
x + y = 90
50 + y = 90
y = 90 - 50
y = 40
speed of the Hamid ( x) = 50 km/h
speed of the Joseph ( y) = 40 km/h
Hence , the speed of the Hamid & Joseph is 50 km/ h & 40 km/h.
HOPE THIS WILL HELP YOU...
Anonymous:
Great thanks mam !
Answered by
3
Let the speed of Joseph = xkm/h
Let the speed of Hamid = ykm/h
When approaching one another, combined speed = (x+y)km/h
Time taken to meet = 30/(x+y) = 1/3 (20 minutes = 1/3 hours)
x+y = 90 ------ (i)
When moving in opposite direction, combined speed = (x-y)m/h
Time taken for Hamid to catch up = 30/(x-y) = 3
x-y = 10 ---- (ii)
Solving (i) and (ii) simultaneously
x+y = 90
x-y = 10
_______
2x = 80
x = 40
y = 50
∴ Speed of Joseph = 40km/h
Speed of Hamid = 50km/h
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