Places A and B are 100 km apart on a highway. One car starts from A and another from B at the same time. If the cars travel in the same direction at different speeds, they meet in 5 hours. If they travel towards each other, they meet in 1 hour. What are the speeds of the two cars?
Answers
Answer:
Step-by-step explanation:
Solution :-
Let the speed of 1st car and 2nd car be u km/h and v km/h.
According to the question,
⇒ 5(u - v) = 100
⇒ u - v = 20 ... (i)
⇒ 1(u + v) = 100 ... (ii)
Adding both the equations, we get
⇒ 2u = 120
⇒ u = 60 km/h ... (iii)
Putting this value in equation (ii), we obtain
⇒ v = 40 km/h
Hence, speed of one car = 60 km/h and speed of other car = 40 km/h
Given :-----
- Distance b/w A and B = 100km
- in same direction they meet = after 5 hours
- in opposite direction they meet = after 1 hour .
Formula used :-----
- speed = Distance/Time
Solution :-------
Let speed of Train traveling from A = x km/h
speed of Train traveling from B = y km/h
A/q,
in same direction they take 5 hours to meet, that means faster train , cover distance between them that is 100km.
in same direction usual speed is difference of both,
so,
(x-y) = 100/5
(x-y) = 20 km/h ------------------------- Equation (1)
Now,
in opposite direction they take 1 hour to meet, that means both cover 100km in one hour .
in opposite direction usual speed is sum of both,
so,
(x+y) = 100/1
(x+y) = 100 km/h ------------------------- Equation (2)
Adding Equation (1) and Equation (2) now, we get,
(x-y) + (x+y) = 20 + 100
→ 2x = 120
→ x = 60 km/h
Putting in any we get,
→ y = 40km/h
so, speed of faster train that started from A was 60km/h and speed of train started from B was 40km/h ..
(Hope it helps you)