Places A and B are 100 km apart on a highway. One car starts from A and another from B at the same time. If the cars travel in the same direction at different speeds, they meet in 5 hours. If they travel towards each other, they meet in 1 hour. What are the speeds of the two cars? ( Solve the question by cross multiplication method )
Answers
Answered by
1
Answer:
Let the speed of car at A be x kmph
and the speed of car at B be y kmph
when the car travel in same direction Relative Speed is x−y
Dist=100km
t=5 hours
∴ Dist =S×T
100=(x−y)5
x−y=20⟶(I)
when car travel in opposite direction Relative Speed is x+y
Dist=100km
t=1 hours
Dist=ST
100=(x+y)1
x+y=100⟶(II)
Solving (I) & (II)
x−y=20
x+y=100
2x=120
x=60km/h
y=40km/h
Speed of the car at A =60 km/h
Speed of the car at B=40 km/h
The difference of speeds is 60−40=20
Answered by
2
Answer:
Let the speed of car at A be x km/h
and the speed of car at B be y km/h
As per the question,
5x - 5y = 100
x - y = 20 ... (1)
and x + y = 100 ... (2)
Solving (1) and (2), we get,
x = 60 and y = 40
Speed of the car at A = 60 km/h
Speed of the car at B = 40 km/h
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