places A and B are 100 KM apart on the highway. one car starts from A and another from B at the same time. if the car travel in the same direction at a constant speed, they meet in 5 hours. if they travel towards each other they meet in 1 hour. what is the speed of the two cars
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If the car is moving in opposite durection it takes 1hr
So, sum of their speed is 100km/hr
Also they took 5hr to meet if travelling in same direction
Let the speed ofcar A be xkn/hr
So speed of carB is 100-x km/hr
Thus,
5*x =5(100-x)
X = 50
So speed of carA = 50km/hr
And car B is 50km/hr(100-50)
So, sum of their speed is 100km/hr
Also they took 5hr to meet if travelling in same direction
Let the speed ofcar A be xkn/hr
So speed of carB is 100-x km/hr
Thus,
5*x =5(100-x)
X = 50
So speed of carA = 50km/hr
And car B is 50km/hr(100-50)
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Answer:
Let the speed of car at A be x km/h
and the speed of car at B be y km/h
As per the question,
5x - 5y = 100
x - y = 20 ... (1)
and x + y = 100 ... (2)
Solving (1) and (2), we get,
x = 60 and y = 40
Speed of the car at A = 60 km/h
Speed of the car at B = 40 km/h
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