places A and B are 80 km apart and 2 bikes travels from A and B speed of bike start from A is greater than speed of bike start from B if there travel same direction then they meet after 8 hours and if they Travels opposite direction they meet after 1 hour 20 minutes find speed of both bikes
Answers
Answer:
speed if bomez are 10 km per hour
Answer:
The speed of first bike is 30.075 km/h
The speed of second bike is 30.075 km/h .
Step-by-step explanation:
Given as :
The distance between two Places A and B = D = 80 km
Let The speed of bike from place A = v km / h
Let The speed of bike from place B = u km/h
When bikes travel in same direction
Relative speed of bikers = (v - u) km/h
The time taken by both bikes to meet = T = 8 hours
According to question
∵ Distance = Speed × Time
Or, 80 km = (v - u) km/h × 8 h
Or, v - u =
i.e v - u = 10 km/h .........1
Again
When bikes travel in opposite direction
Relative speed of bikers = (v + u) km/h
The time taken by both bikes to meet = t = 1 hour + 20 min
i.e t = ( 1 + ) hour
Or, t =1.33 hours
According to question
∵ Distance = Speed × Time
Or, 80 km = (v + u) km/h × 1.33 h
Or, v + u =
i.e v + u = 60.15 km/h .........2
Solving eq 1 and 2
(v + u) + (v - u) = 60.15 + 10
Or, (v + v) + (u - u) = 70.15
Or, 2 v + 0 = 70.15
Or, v =
i.e v = 35.075 km/h
So, the speed of first bike = v = 30.075 km/h
put the value of v into eq 2
∵ v + u = 60.15
Or, 30.075 + u = 60.15
Or, u = 60.15 - 30.075
i.e u = 30.075 km/h
So, the speed of second bike = u = 30.075 km/h
Hence, The speed of first bike is 30.075 km/h and The speed of second bike is 30.075 km/h . Answer