Question

ple
Find acceleration of 4 kg & 6 kg in the given scenario.
5 ms-2

Answer 1

$\huge\red{Answer}$

➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️

☆☞ [ Vernified answer ]☜☆

the equation of net force on 6kg is given as

6×10−T=6a

equation of net force on 4kg is given as

T−4×10=4a

now add the above two equations

6×10−(4×10)=(6+4)×a

60 - 40 = 10a

a = 2m/s

2

So 6 kg will accelerate downwards while 4 kg will accelerate upwards

with acceleration 2 m/s

2

now in order to find the tension force

T−4×10=4×2

T = 48N

So the tension in the string is 48 N

jai siya ram☺ __/\__

➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️

¯\_(ツ)_/¯

Answer 2

$\huge\boxed{\fcolorbox{black}{pink}{Question:- }}$

ple

Find acceleration of 4 kg & 6 kg in the given scenario.

5 ms-2

$\huge\red{Answer:-}$

➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡

☆☞ [ Verified answer ]☜☆

6×10−T=6a--------------equation 1

T−4×10=4a----------equation 2

now add the above two equations

6×10−(4×10)=(6+4)×a

60 - 40 = 10a

a = 2m/s

So 6 kg will accelerate downwards while 4 kg will accelerate upwards

T−4×10=4×2

T = 48N

So the tension in the string is 48 N

jai siya ram☺ __/\__

➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️➡️

¯\_(ツ)_/¯

plz mark me as the brainliest

$\huge\green{Thanks}$