Question

A 100 g iron ball is cooled down from 100°C to 30°C. Calculate the loss of heat if specific heat of
iron is 4.8 × 102
J kg1
°C1
.

Answer 1

Answer:

The specific heat of is 4.8j/kg*c. So, the loss of heat when 100 g of iron is cooled down from Temperature of 100 degrees celcius to a Temperature of 30 degrees celcius is 33.6 J.

Answer 2

Answer:

Specific heat of Iron is : 4.8 × 10^2

J kg^-1

°C^-1

Explanation:

So, It becomes

4800

0.1 kg 70 ºC

Now

the answer is 3360 J