Question

pleas answer this question​

Answer 1

Given:-

1. In ∆ABC , AB is 24 cm , AC is 26 cm and BC is 10 cm.

To find:-

• Angle B.

Solution:-

• First we will prove that, ∆ABC is right angled triangle.

We know that,

Pythagoras theorem is :

$\boxed{ \bold{ {Base}^{2} + Perpendicular^{2} = {Hypotenuse}^{2} }}$

Let,

Perpendicular =AB = 24 cm

Hypotenuse = AC = 26 cm

Base = BC = 10 cm.

So,

$\implies \sf {(24)}^{2} + {(10)}^{2} = {(26)}^{2}$

$\implies \sf 576 + 100 = 676$

$\implies \sf 676 = 676$

Thus, ∆ABC is right angled triangle.

Angle B is of 90° beacuse AB is perpendicular which is forming on base BC. And ∆ABC is right angled triangle.

Therefore,

$\large \boxed{ \bold{ \angle B = 90 \degree}}$