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y=180-(50+85) (< sum of a triangle)
180-135
45
ACB=45+40
=85
x=180-(50+85)
180-135
45
180-135
45
ACB=45+40
=85
x=180-(50+85)
180-135
45
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Answered by
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In triangle ACD
a+d+c=180°
50+85+y=180
Y=180-135
y= 45°
now in triangle ABC
a+b+C=180°
50+(45+40) +x=180
50+85+x=180
x=180-135
x=45°
so x and Y are both 45°
a+d+c=180°
50+85+y=180
Y=180-135
y= 45°
now in triangle ABC
a+b+C=180°
50+(45+40) +x=180
50+85+x=180
x=180-135
x=45°
so x and Y are both 45°
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