Pleas help if anyone can solve
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1. Given 100cm^3 of 0.10
so, 100cm^3 = 0.100 dm^3
Number of Mass of solute = 0.10 moles * 0.100 dm^3
= 0.10
We know that molar mass of HNO3 = 63g
So, required mass of solute = 63 * 0.10
= 6.3g
2) Same as 1st one
Given 500 cm^3 = 0.500 dm^3
Number of mass of solute = 0.20 moles * 0.500 dm^3
= 0.10 moles
We know that molar mass of potassium dichro = 294 mol
Mass of solute needed = 0.10 * 294
= 29.4 g
Hope this helps!
so, 100cm^3 = 0.100 dm^3
Number of Mass of solute = 0.10 moles * 0.100 dm^3
= 0.10
We know that molar mass of HNO3 = 63g
So, required mass of solute = 63 * 0.10
= 6.3g
2) Same as 1st one
Given 500 cm^3 = 0.500 dm^3
Number of mass of solute = 0.20 moles * 0.500 dm^3
= 0.10 moles
We know that molar mass of potassium dichro = 294 mol
Mass of solute needed = 0.10 * 294
= 29.4 g
Hope this helps!
manahil1:
100 will be divided directly by 1000 why you have done in 2 steps
Because brainly team members are removing my comment for not explaining each step clearly. So that is the reason I have explained each step clearly.
How did you get 0.10 ? Because after multiplying the answer is 0.01
Whcih step?
which step?
Which formula are you putting for mass can you explain please?
The answer in which you get 0.10?
Correct your 1st answer. It should be 0.10 × 0.100 = 0.01
Yeah
Answered by
0
First of all you should convert volume in cm^3 to litres because Molarity is no. of moles of solute in one litre of solution. 1 Litre is equal to 1 dm^3 and 1 dm^3 is equal to 10^3 cm^3
(a)
100 cm^3 = 0.1 × 10^3 cm^3 = 0.1 dm^3 = 0.1 L
[∵ 10^3 cm^3 = dm^3 = L]
n = MV
n = 0.1 × 0.1
n = 0.01 mol of HNO3
Weight of HNO3 = Moles × Molecular weight of HNO3
= 0.01 mol × 63 g/mol
= 0.63 g
_______________
(b)
500 cm^3 = 0.5 × 10^3 cm^3 = 0.5 dm^3 = 0.5 L
n = MV
n = 0.2 × 0.5
n = 0.1 mol of Potassium di-chromate
Weight = Moles × Molecular weight of K2Cr2O7
= 0.1 mol × 294 g/mol
= 29.4 g
(a)
100 cm^3 = 0.1 × 10^3 cm^3 = 0.1 dm^3 = 0.1 L
[∵ 10^3 cm^3 = dm^3 = L]
n = MV
n = 0.1 × 0.1
n = 0.01 mol of HNO3
Weight of HNO3 = Moles × Molecular weight of HNO3
= 0.01 mol × 63 g/mol
= 0.63 g
_______________
(b)
500 cm^3 = 0.5 × 10^3 cm^3 = 0.5 dm^3 = 0.5 L
n = MV
n = 0.2 × 0.5
n = 0.1 mol of Potassium di-chromate
Weight = Moles × Molecular weight of K2Cr2O7
= 0.1 mol × 294 g/mol
= 29.4 g
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