please also my question
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hii there!! here's ur answer :--
V=9v
R=(0.2,0.3,0.4,0.5 and 12) ohm
I=V/R
I=9/0.2+0.3+0.4+0.5+12
I=9/13.4
I=0.672
so, current flowing across 12 ohm is also 0.672 ,since all are connected in series.
V=9v
R=(0.2,0.3,0.4,0.5 and 12) ohm
I=V/R
I=9/0.2+0.3+0.4+0.5+12
I=9/13.4
I=0.672
so, current flowing across 12 ohm is also 0.672 ,since all are connected in series.
Aaujla:
thanks g
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