Question

please anՏᗯᗴᖇᖇ..IT.....................​

Answer 1

Step-by-step explanation:

sin theta=5/13

in a triangle ABC,

let AB=5 BC=13 and AC=√BC^2 -AB^2=12

cos theta=12/13

tan theta=5/12

cosec theta-13/5

sec theta-13/12

cot theta=12/5

Answer 2

so, here the answer of this question ...