Question

Please añßw3r 0l3àß3

Answer 1

Answer:

$\huge \mathfrak \red{ \boxed{ \pink{ \boxed{solution}}}} \\ \\ we \: have \: \\ \\ x = a \: sin \theta \: \\ \red{ y = a \: cos \theta} \\ \\ adding \: both \: after \: squairing \\ \\ {x}^{2} + {y}^{2} = \red{{a}^{2} {sin}^{2} \theta \: + {a}^{2} {cos}^{2} \theta} \\ \\ {x}^{2} + {y}^{2} = {a}^{2} \bigg( {sin}^{2} \theta \: + {cos}^{2} \theta \bigg) \\ \\ so \\ \\ \boxed{{x}^{2} + {y}^{2} = {a}^{2} }$