Question

please ans........................​

Answer 1

Step-by-step explanation:

${\bf{\underline{\purple{\huge{Answer}}}}}$

The answer is $<marquee>1/4</marquee>$

Answer 2

${}{ \huge{ \underline{ \red{Question - }}}}$

∆ABC and ∆BDE are two equilateral triangles such that D is the midpoint of BC. Then,

ar(∆BDE): ar(∆ABC) = ?

${} \huge \blue{Solution - }$

Given: ∆ABC and ∆BDE are two equilateral triangles, D is the midpoint of BC.

Consider ΔABC

Here, let AB = BC = AC = x cm (equilateral triangle)

Now, consider ΔBED

Here,

BD = 1/2 BC

∴ BD = ED = EB = 1/2 BC = x/2 (equilateral triangle)

Area of the equilateral triangle is given by:

√3/4a^2

∴ ar(∆BDE): ar(∆ABC) =

$\frac{ \sqrt{3} }{4} \times (\frac{x}{2} ) {}^{2}$

:

$\frac{ \sqrt{3} }{4} {x}^{2}$

=1/4:4

=1:4

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