Question

please ans. attached que. no. 9

Answer 1

first you have to multiply the power,
then,subtract the power of denominator after multiplying.
do the same process in all 3 x's.
then add and subtract the power with take the x common.
then the will be zero. and the answer. will be 1

please mark me as a brainliest.

Answer 2

Answer:

Option (b) - 1.

Explanation:

$= \ \textgreater \ Given : ( \frac{x^b}{x^c}) ^{b+c-a} * ( \frac{x^c}{x^a}) ^{c+a-b} * ( \frac{x^a}{x^b} )^{a+b-c}$

$= \ \textgreater \ x^{(b-c)(b+c-a)} * x^{(c-a)(c+a-b)} * x^{(a-b)(a+b-c)}$

$= \ \textgreater \ x^{(b-c)(b+c-a) + (c-a)(c+a-b)+(a-b)(a+b-c)}$

$= \ \textgreater \ x^{b^2-ab-c^2+ca+c^2 -bc+ba-a^2-b^2+bc-ca+a^2}$

$= \ \textgreater \ x^0$

1.


Hope this helps!