please ans ques no. 50 given
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Name the points of 30 Ω resistance as C and D, for convenience,
We know that, Effective resistance in Series is R1+R2 +R3+.....Rn (If n resistances are there),
And we also knew that, Effective Resistance in Parallel is (1)/(1/R1 + 1/R2 + ......+ 1/Rn) ( If n resistances are there)
Now, We know that resistances between C and D in the right side are in Series,
=> Effective Resistance is 20 Ω + 10 Ω + 20 Ω,
=> Effective resistance towards right side is 50 Ω,
Now, 50 Ω resistance is parallel with 30 Ω resistance,
So the effective resistance again will be (1)/(1/50 Ω + 1/30) Ω,
=> 1/8/150 = 150/8 = 18.75 Ω
Now, This resistance is in series with 10 Ω and 10 Ω that are between A and B,
=> Effective resistance is 20 Ω + 18.75 Ω = 38.75 Ω,
So therefore the effective resistance Between A and B is nearly 38.75 Ω,
Sorry for the delay, Calculations made me late,
Hope you understand, Have a Great day !, Advance Merry Christmas !
Thanking you, Bunti 360 !
We know that, Effective resistance in Series is R1+R2 +R3+.....Rn (If n resistances are there),
And we also knew that, Effective Resistance in Parallel is (1)/(1/R1 + 1/R2 + ......+ 1/Rn) ( If n resistances are there)
Now, We know that resistances between C and D in the right side are in Series,
=> Effective Resistance is 20 Ω + 10 Ω + 20 Ω,
=> Effective resistance towards right side is 50 Ω,
Now, 50 Ω resistance is parallel with 30 Ω resistance,
So the effective resistance again will be (1)/(1/50 Ω + 1/30) Ω,
=> 1/8/150 = 150/8 = 18.75 Ω
Now, This resistance is in series with 10 Ω and 10 Ω that are between A and B,
=> Effective resistance is 20 Ω + 18.75 Ω = 38.75 Ω,
So therefore the effective resistance Between A and B is nearly 38.75 Ω,
Sorry for the delay, Calculations made me late,
Hope you understand, Have a Great day !, Advance Merry Christmas !
Thanking you, Bunti 360 !
student59:
I am saying that how can u add 10 ohm plus 10 ohm to get 20 ohm
they are parallel
that should be 1/10 +1/10 =2/10
=10/2 is equal to 5
they r not in parallel ... they r in series ... current in them is same
look at diagram they looks parallel at left side of diagram
don't just look and say .... connect points A and B to a battery and then see, the current in both the resistors is same.
always use basic concepts ...
ok
:)
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Answer:
Explanat1) According, to the third law of motion by newton, every action has an equal and opposite reaction.
2) so, if the bullet exerts a momentum when going forward, same amount of momentum will push the gun backward
3) Hence, the momentum of both would be equal
10 g * v = 1000 g * 5 m/s
v = 500 m/sion:
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