Question

Please ans the 15th question with steps I will mark as brainlist

Answer 1

Given price of car = 341700

In first year price decreased by 20%.

It means 20% of 341700
= 20/100 × 341700
= 6834000/100
= 68340

So the price after 1 year = 341700 - 68340
= 273360.

In second year price reduced 5% of previous year.

So 5% of previous year = 5/100 × 273360
= 1366800/100
= 13668

At end of 2nd year price of car = 273360-13668
= Rs. 259692

If you satisfied mark it brainliest.

Answer 2

Price of car = Rs.341700

 

Year I

Decrease by 20% of Original price

 

Decrease/Loss (Rs) = Decrease/Loss % / 100 × Original Price 

 

                                 = 20 / 100 × 341700

 

                                 = Rs. 68340

 

Resale Price in year I = 341700 - 68340

 

                                   = Rs.273360

 

Year II

 

Decrease by 5% of Year I resale price

 

Decrease/Loss (Rs) = Decrease/Loss % / 100 × Year I resale price

 

                                 = 5 / 100 × 273360

 

                                 = Rs.13668

 

Resale Price in year II = 273360 - 13668

 

                                    = Rs.259692

 

 

☺ Hope this Helps ☺