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Answer:
cos θ = 4/5
tanθ = 3/4
Step-by-step explanation:
by Pythagoras theorem we can find out the value of base. we already know the value of perpendicular and hypotenuse coz we know the value of sin θ is perpendicular/hypotenuse
now when we know all three values, we can find out the required ratios
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▲ABC be a right angled at B
Let, ∠ ACB=Θ
Given that, sin = 3/5
AB/AC = 3/5
Let, AB = 3x
then AC = 5x
In right angled ▲ABC,
By Pythagoras theorem,
We get,
hypo²=side²+side²
(5x)²= (3x)² + BC²
BC² = (5x)² -(3x)²
BC² = (5x)²-(3x)²
BC² = 25x²-9x²
BC²=16x²
taking square root,
BC=4x
(i) cos 0 = Base/ Hypotenuse
BC / AC = 4x /5x = 4/5
(ii) tan 0 = perpendicular/Base
AB/BC=3x/4x=3/4
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