Math, asked by TANU81, 1 year ago

Please ans this.....

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Answered by RishabhBansal
9
Hey!!!

Good Afternoon

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let the fixed rent be Rs.x and the mess charges be Rs.y

Then ATQ,

Case 1

=> x + 2y = 3900

=> x = 3900 - 2y ------(1)

Case 2

=> x + 5y = 7500

=> x = 7500 - 5y -------(2)

Equating (1) and (2)

=> 3900 - 2y = 7500 - 5y

=> 3y = 3600

=> y = 1200

Using y in (1)

=> x = 3900 - 2(1200)

=> x = 1500

Thus the fixed rent is Rs.1500 and mess charges is Rs.1200.

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Hope this helps ✌️

RD Sucks
Answered by Thatsomeone
8
Let the rent of the house be "Rs x " and the mess charges for a person be " Rs y "

The total monthly expenditure is Rs 3900 for 2 people so we get equation

x + 2y = 3900

And Rs 7500 for 5 people so we get another equation

x + 5y = 7500

Subtracting equation 1 from equation 2 we get

3y = 3600

y = 1200

putting ( y = 1200 ) in equation 1

x + 2( 1200 ) = 3900

x = 3900 - 2400

x = 1500

so the monthly fixed rent us Rs 1500 and mess charges per head is Rs 1200
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