Physics, asked by kayashri203, 8 months ago

please ans this question


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Answered by Ekaro
5

Answer :

\implies\sf\:I= I_ocos\omega t

\implies\sf\:I_{av}=\:<I_ocos\omega t>

\displaystyle{\implies\sf\:I_{av}=I_0\:\dfrac{\int{cos\omega t\:dt}}{\int{dt}}}

\implies\sf\:I_{av}=I_o\:\dfrac{{\large [}\dfrac{sin\omega t}{\omega}{\large ]}_0^{\frac{\pi}{\omega}}}{[t]_0^{\frac{\pi}{\omega}}}

\implies\sf\:I_{av}=\dfrac{I_o}{\pi}\:[sin\omega(\frac{\pi}{\omega})-sin0]

\implies\sf\:I_{av}=\dfrac{I_o}{\pi}\:[sin\pi-sin0]

\implies\sf\:I_{av}=I_0\:[0-0]

\implies\:\boxed{\bf{\purple{I_{av}=0}}}

Cheers!

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