Question

please ans trignometry​

Answer 1

Step-by-step explanation:

= (sin²αsin²β + sin²αcos²β + cos²α) + (sin²(2π+α) + cos²(6π-α)+1) / (sin²(π/3 - 4π) + cos²(8π+π/3) + 2)

= [ sin²α(sin²β+cos²β)+cos²α + sin²(2π+α) + cos²(8π-(2π+α) +1 ] / ( sin²(π/3-4π) + cos²(12π-(4π-π/3)) + 2 )

= ( sin²α(1)+cos²α + sin²(2π+α)+cos²(2π+α)+1 )/(sin²(π/3-4π)+cos²(4π-π/3)+2 )

= (1 + 1 + 1)/ ( 1 + 2)

= 3/3

= 1