please ans with formulae
Attachments:
Answers
Answered by
1
side = 4.1
diagonal = 1.8
AO = 1.8/2 = 0.9 As diagonals bisect each other
As AOB is right angled triangle
OB = √ AB^2 - AO^2 = √4.1^2 - 0.9^2
= √ 16.81 - 0.81
= √ 16
= 4
So Area of AOB = 1/2 .AO. OB= 1/2 . 0.9 × 4
= 1.8
So area of rhombus = 4× 1.8 = 7.2
diagonal = 1.8
AO = 1.8/2 = 0.9 As diagonals bisect each other
As AOB is right angled triangle
OB = √ AB^2 - AO^2 = √4.1^2 - 0.9^2
= √ 16.81 - 0.81
= √ 16
= 4
So Area of AOB = 1/2 .AO. OB= 1/2 . 0.9 × 4
= 1.8
So area of rhombus = 4× 1.8 = 7.2
Attachments:
Answered by
0
Answer:
Step-by-step explanation:
As it is a rhombus . Area = 1/2 ×4.1√4(4.1)^2 - (1.8)^2 = 7.2cmsq
Similar questions