please ans without l hospital rule limit class 12th
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Step-by-step explanation:
α = lim (n->inf) [ (1³-1²) + (2³-2²)+(3³-3²)+...+(n³-n²)]/n^4
=> α = lim(n->inf) [ sigma(n=1 to n=inf) (n³-n²)/n^4 ]
=> α = (sigma(n=1 to inf) lim(n->inf) (n³/n^4 - n²/n^4)
=> α = (sigma(n=1 to inf) lim(n->inf) (1/n - 1/n²)
=> α = (sigma(n=1 to inf) ( 1/infi - 1/inf²)
=> α = (sigma(n=1 to inf) (0-0)
=> α = 0
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Answer :
1/4
Solution:
Please refer to the attachments .
Note:
★ Sum of n natural numbers is given by ;
1 + 2 + 3 + . . .+ n = (n/2)•(n + 1)
★ Sum of squares of n natural numbers is given by ;
1² + 2² + 3² + . . . + n² = (n/6)•(n + 1)•(2n + 1)
★ Sum of cubes of n natural numbers is given by ;
1³ + 2³ + 3³ + . . . + n³ = [ (n/2)•(n + 1) ]²
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