Question

Please answer..................!!!

Answer 1

see this figure ,
let acceleration of system of mass is a
and we let motion of string in polley is left to right .
for 8 kg
————
T1 - mg = ma
T1 - 8g = 8a -----(1)

for 6kg
———— ——
T2 + 6g - T1 = 6a -------(2)

for 4kg
—————
4g - T2 = 4a ----------(3)

add eqn (1) and (2)
T2 - 2g = 14a -------(4)

now, for equation (4) and (3)
2g = 18a

a = 20/18 = 10/9 m/s²

so, T2 = 2g +14a = 20 + 140/9 =320/9 N

and T1 = 8g + 8a = 80 + 80/9 = 800/9 N

here ask Tension between 6 and 4kg .
e.g T2 = 320/9 N