please answer
13 a and b part
Answers
Step-by-step explanation:
Q13
a) let the fraction be x/y
now according to the question
x+y=18 - (i)
and
x/y+2 = 1/3 - (ii)
solving eq (ii)
x/y+2 = 1/3
3x= y+2
3x-y=2 - (iii)
now solving eq (i) & (ii) by elimination method
adding eq i and iii
3x+x-y+y = 18+2
4x=20
x=5
putting value of x in eq i
x+y=18
y=18-5
y=13
fraction = 5/13
b) let the fraction be x/y
now according to the question
x+y=7 - (i)
& 4x = 5y-8 -(ii)
solving eq(ii)
4x=5y-8
5y-4x=8 (iii)
solving eq i and ii by elimination method
multiplying eq (i) by 4 and adding to eq (iii)
4x+4y+5y-4x = 28+8
9y = 36
y = 4
putting value of y in eq(i)
x+y=7
x=7-4
x=3
fraction= 3/4
I m not sure about the answer so u can recheck it.
a.
Let the numerator be x.
Let the denominator be y.
The fraction becomes x/y
The sum of numerator and denominator is 18.
x + y = 18.
Let the above equation be equation 1.
If the denominator is increased by 2, the fraction reduces to 1/3.
Let the above equation be equation 2.
Adding equations 1 and 2.
The numerator is 5.
Substitute x = 5 in equation 1.
The denominator is 13.
The fraction is 5/13
b.
Let the numerator be x.
Let the denominator be y.
The fraction becomes x/y
The sum of numerator and denominator is 7.
x + y = 7.
Multiplying 4 on both sides.
4 ( x + y ) = 7 × 4
4x + 4y = 28
Let the above equation be equation 1.
Four times the numerator is 8 less than five times the denominator.
4x = 5y -8
5y - 4x = 8
Let the above equation be equation 2.
Adding equations 1 and 2
The denominator is 4.
Substitute y = 4 in equation 2.