Question

please answer 21st question

Answer 1

your answer is zero
Assume is equal to b is equal to C is equal to 2
it will satisfy the equation
a+b+c=6

Answer 2

a + b + c = 6

=> 0 = 6 - a - b - c

=> 0 = 2 + 2 + 2 - a - b - c

=> (2-a) (2-b)(2-c) = 0

Using identity,

If ( x + y + z) = 0,
then x^3 + y^3 + z^3 = 3xyz
____________________________

(2-a)^3 +(2-b)^3 + (2-c)^3 = 3(2-a)(2-b)(2-c) --------(1)

____________________________

Now,

(2-a)^3 + (2-y)^3 +(2-z)^3 - 3(2-a)(2-b)(2-c)

= 3(2-a)(2-b)(2-c) - 3(2-a)(2-b)(2-c)

= 0