Math, asked by Arayansingh12, 1 year ago

write the following in exponential form

{a} product of 4 cubed and 5 squared
{b}sum of 7 raised to the power of 4 and 9 raised to the power 5.

Answers

Answered by Abhinav2904
10
a. 89 is the first answer
Answered by tardymanchester
2

Answer:

a) 4^3\times 5^2=1\times 10^4 +6 \times 10^3+0\times 10^2+0\times 10^1

b) 7^4+9^5=6\times 10^5+1\times 10^4 +4\times 10^3+5\times 10^2+0\times 10^1

Step-by-step explanation:

Given : {a} product of 4 cubed and 5 squared

{b}sum of 7 raised to the power of 4 and 9 raised to the power 5.

To Write in exponential form :

{a} product of 4 cubed and 5 squared  = 4^3\times 5^2

First we solve this expression

4^3\times 5^2

=64\times 25

=1600

In exponential form - 1\times 10^4 +6 \times 10^3+0\times 10^2+0\times 10^1

{b} sum of 7 raised to the power of 4 and 9 raised to the power 5 = 7^4+9^5

First we solve this expression

7^4+9^5

=2401\times 59049

=61450

In exponential form - 6\times 10^5+1\times 10^4 +4\times 10^3+5\times 10^2+0\times 10^1

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