Question

please answer...............​

Answer 1

7^(1/49) × 7^(2x) = 7^(8)

7^(-2) × 7^(2x) = 7^(8)

-2 + 2x = 8

2x = 10

X = 5

Answer 2

Answer:

$\frac{1}{49} \times {7}^{2x} = {7}^{8} \\ we \: can \: write \\ \\ \frac{1}{49} as \frac{1 }{ {7}^{2} } and \: as \: {7}^{ - 2} \\ {7}^{ - 2} \times {7}^{2x} = {7}^{8} \\ {7}^{ - 2 + 2x} = {7}^{8} ( {a}^{m} + {a}^{n} = {a}^{m + n} ) \\ as \: bases \: equal \: powers \: must \: be \: equal \\ - 2 + 2x = 8 \\ 2x = 10 \\ x = \frac{10}{2} \\ x = 5 \\ hope \: it \: helps \: u \:$