Question

Please answer 3 part. Please as fast as you can. Need help. ​

Answer 1

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☆ ANSWER:-

▪︎ Given:-

$\sf\bullet\: x = \frac{ - 5}{3} \\ \\ \sf\bullet \: y = \frac{2}{7} \\ \\ \sf\bullet \: z = \frac{1}{ - 4} = \frac{ - 1}{4}$

▪︎ To Verify:-

$\tt\leadsto(x + y) \div z = x \div z + y \div z$

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▪︎ Concept Used:-

• BODMAS (Bracket Open Division Multiplication Addition Subtraction)

• x/y ÷ p/q = x/y × q/p

• Concept of LCM.

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▪︎ Now,

• Lets put the value of x, y, and z in given equation.

$\sf \mapsto(x + y) \div z = x \div z + y \div z \\ \\ \sf \mapsto (\frac{ - 5}{3} + \frac{2}{7}) \div (\frac{ - 1}{4} ) = \frac{ - 5}{3} \div \frac{ - 1}{4} + \frac{2}{7} \div \frac{ - 1}{4} \\ \\ \sf \mapsto( \frac{ - 35 + 6}{21}) \div \frac{ - 1}{4} = \frac{ - 5}{3} \times \frac{ - 4}{1} + \frac{2}{7} \times \frac{ - 4}{1} \\ \\ \sf \mapsto( \frac{ - 29}{21}) \times \frac{ - 4}{1} = \frac{20}{3} + ( \frac{ - 8}{7} ) \\ \\ \sf \mapsto \frac{ 116}{21} = \frac{140 - 24}{21} \\ \\ \sf \red{\fbox{\mapsto \frac{ 116}{21} = \frac{ 116}{21} }}$

☆ HENCE VERIFIED...

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