Question

please answer?.........​

Answer 1

Step-by-step explanation:

rhombus =10cm

diagonal =12cm

perimeter of a rhombus = 10+10+10+10

= 40

diagonal. = 12cm

so, 40+12=52

Answer 2

Answer:

The diagonals in a rhombus are perpendicular , and bisect each other

Given length of side is 10 cm and one diagonal as 12 cm we can find the length of other diagonal

From the above figure let DB be the 12 cm diagonal,now OB and OD are 6 cm

Now consider triangle AOB ,this is a right andled triangle and we know AB=10cm and OB=6cm ,using Pythagoras theorem we can find out lenth of OA as 8cm ,so length of diagonal AC is 2*8=16cm

Area of rhombus is product of diagonal divided by 2, 16*12/2=96 sq.cm

Perimeter of rhombus =4( side)

= 4*10

= 40 cm

Step-by-step explanation:

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