Question

Please answer..........

Answer 1

Hey

:) Answer Of Your Question (:

x-y=4

→x=y+4

xy=12

(y+4)×y=12

→y^2+4y=12

→y^2+4y-12=0

→y^2+6y-2y-12=0

→y(y+6)-2(y+6)=0

→(y+6)(y-2)=0

Now,

(y+6)=0

→y=-6

or,

(y-2)=0

→y=2

So, y=2

Now ,

xy=12

→2x=12

→x=6

so, x=6 and y=2

Now,

(x^3-y^3)

=(6^3-2^3)

=(216-8)

=208

so, (x^3-y^3)=208

Hope My Answer Helped