Math, asked by joshinachacko81, 1 month ago

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Answered by saachir41

0

Step-by-step explanation:

Area to be painted = area of the walls + area of ceiling

=2(hl+hb)+lb

=[2×(7×15+7×10)+(15×10)]=500 sq m

No. of cans required =

100

500

=5

Hence, 5 cans are required to paint the walls and the ceiling of the cuboidal hall.

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