Physics, asked by arpita2280, 1 year ago

please answer ...........

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Answered by vrrunda

hey your answer is b)BA^2cos¢

TheConqueror: vrrunda what about the cross product?

vrrunda: cross product pf vector A and B =ABdin¢n^

vrrunda: of*

TheConqueror: hmm

vrrunda: i gave the second one question of you so plzz there make me as brainliest answer

arpita2280: ok

vrrunda: plzzz do fast

arpita2280: i already do that

vrrunda: in your second question A=cos^2¢+sin^4¢

TheConqueror: you did not apply cross product in this answer

Answered by TheConqueror

c)BA²sinΩcosΩ
as ×product=BASinΩ
while .=(BAsinΩ(AcosΩ))

arpita2280: no i don't know

arpita2280: that is a home task

TheConqueror: doesn't matter

TheConqueror: you can discuss this in class tomorrow and then let me know.

arpita2280: ok

TheConqueror: :)

TheConqueror: answer is 0

TheConqueror: as the cross product will have 90° angle with A vector and B vector both

TheConqueror: i did not get edit option so telling u here

TheConqueror: cos90°is 0 so answer will be 0 i. e. d option

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