please answer ...........
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hey your answer is b)BA^2cos¢
TheConqueror:
vrrunda what about the cross product?
cross product pf vector A and B =ABdin¢n^
of*
hmm
i gave the second one question of you so plzz there make me as brainliest answer
ok
plzzz do fast
i already do that
in your second question A=cos^2¢+sin^4¢
you did not apply cross product in this answer
Answered by
1
c)BA²sinΩcosΩ
as ×product=BASinΩ
while .=(BAsinΩ(AcosΩ))
as ×product=BASinΩ
while .=(BAsinΩ(AcosΩ))
no i don't know
that is a home task
doesn't matter
you can discuss this in class tomorrow and then let me know.
ok
:)
answer is 0
as the cross product will have 90° angle with A vector and B vector both
i did not get edit option so telling u here
cos90°is 0 so answer will be 0 i. e. d option
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