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Given n(p)=18-x, n(q)=24+x,n(pUq)=34
Firstly n(p∆q)=n(pUq)-n(pnq)
Now,
we know that ,
n(pUq)=n(p)+n(q)-n(pnq)
34=18-x+24+x-n(pnq)
34=18+24-n(pnq)
34=42-n(pnq)
n(pnq)=8
so,
n(p∆q)=n(pUq)-n(pnq)
n(p∆q)=34-8
n(p∆q)=26
Hope you find it easy to understand.
Please mark me as brainliest!!!
Firstly n(p∆q)=n(pUq)-n(pnq)
Now,
we know that ,
n(pUq)=n(p)+n(q)-n(pnq)
34=18-x+24+x-n(pnq)
34=18+24-n(pnq)
34=42-n(pnq)
n(pnq)=8
so,
n(p∆q)=n(pUq)-n(pnq)
n(p∆q)=34-8
n(p∆q)=26
Hope you find it easy to understand.
Please mark me as brainliest!!!
Answered by
0
Answer:
your answer is 26 ok thnx brainliest plsss...
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