Question

in a neutral sphere, 5×10^21 electrons are present. if 10% electrons are removed, then calculate the charge on the sphere.

Answer 1

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Answer 2

Answer:

The net charge on the sphere will be 80 C.

Explanation:

Given that,

Present electron $e= 5\times10^{21}$

Percentage of removed electron = 10%

So, the number of electron removed

$n = \dfrac{10}{100}\times5\times10^{21}$

$n=5\times10^{20}$

The net charge removed is

$q=-1.6\times10^{-19}\times5\times10^{20}$

$q = -80\ C$

The net charge on the sphere$q = +80 C$

Hence,The net charge on the sphere will be 80 C.