Question

please answer ❤️.....​

Answer 1

we know that...

concentration=no.ofmoles/volume

the rate will be 1/3 × (1/3)^2

=1/3 × 1/9

=1/27

Answer 2

GOOD MORNING

Given Rate Equation is

Rate = k [ A ] × [ B ]² ... Equation i

IF WE REDUCE VOLUME DEFINITELY CONCENTRATION WILL INCREASE BECOZ VOLUME IS INVERSELY PROPORTIONAL TO CONCENTRATION.

WHEN WE REDUCE VOLUME NEW RATE BECOME.

Rate¹ = k [ 3 A ] × [ 3B ]²

Rate¹ = k 3 [ A ] × 9 [ B ]

Rate¹ = k 27 [ A ] × [ B ] ... Equation ii

FROM EQUATION I AND II WE HAVE

Rate /Rate¹ = 1/27

Rate¹ = 27 × Rate.

So, New Rate of reaction will increase 27 times the original rate on reducing volume by 1/3

Rate¹ repsent new rate.