please answer 9th question and also show love for charlie puth
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PA and PB are tangents.Therefore angle OAP = angle OBP = 90°.
In a quadrilateral the sum of angles is equal to 360°.
Therefore OAP + OBP + AOB + APB = 360°
Which implies AOB + APB = 180°
Since sum of opposite angles of the quadrilateral = 180°.
It is a cyclic quadrilateral.
In a quadrilateral the sum of angles is equal to 360°.
Therefore OAP + OBP + AOB + APB = 360°
Which implies AOB + APB = 180°
Since sum of opposite angles of the quadrilateral = 180°.
It is a cyclic quadrilateral.
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this would surely bring colours...ie.,answer
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jebakiruba:
ur welcome
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