Question

Please answer all 6 sums...
Don't answer only 1 question....
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Do all please ...
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Answer 1

don't know ans 1

ans2=3yellow chairs

ans3=don't know

ans4=36

ans5=don't know

ans6=

Step-by-step explanation:

ans2=⅗×15=9

⅕×15=3

9+3=12

15-12=3

ans4= 3x+10=60

3x=60-10

x=50/3=16, remainder=2

50-16=34+2=36

father's age =36

son's age =16

ans6=total chocolates=50

divide=50÷2=25

jhony=25-6=19

jhon=25+6=31

Answer 2

Step-by-step explanation:

1) Given

cost of 8 pens and 2 books are equal , which means ==> 8x = 2y

==> 8x - 2y = 0 ----->1

abhinav bought 4pens and 5 books fo $60

so, 4x + 5 y = $60 ----->2

by elimination method of eq 1 & 2

we get y = 10 ( cost of each book)

2) i dont know

3) no. of cartons are 15

no. of pencil boxes in each carton are 15

so, the no. of pencil boxes in 15 cartons are

15x15 =225

no. of pencils in eaxh box are 12

so, now the total no. of pencils are

225x12=2700

he kept 700 pencils which means he sold 2000 pencils

he sold for $200

now cost of each pencil is = 200/2000=0.1$

4) let the age of son be x

then the age of father is 3x

in ten years ,

son's age will be x+10

father's age will be 3x + 10

Given sum of their ages is 60

so x +10 + 3x + 10 = 60 ---->1

4x + 20 = 60

4x = 40

x = 10 ( son's age)

father's age = 3(10) = 30

substituting x in eq 1 we get lhs equal to rhs

5) $ 204 is to be divided among x , y and z

x gets 2 times the amount y got

z gets 3 times the amount y got

so,

x= 2y, y , z= 3y ------>

now 2y + y + 3y = 204

6y = 204

y = 204/6 = 34

y gets 34

x = 2y => 2(34) = 68

z= 3y => 3(34)= 102

check: 34 +68+102= 204

6) let the no. of chocolates johny have be x

then , no. of chocolates john have are x + 6

Given total chocolates are 50

so,

x + x + 6 = 50

2x + 6 = 50

2x =50 - 6

x = 44/2

x = 22 (no. of chocolates johny have)

no . of chocolates john have = 22 + 6 = 28