please answer all of these problems with process
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2)80
3)30+57+angle0=180
angleAOC=180_87
angleAOC=93
and
I triangle oAB OA=OB
Angle OAB=OBA
angle BOA=120
BOA-AOC=BOC
120-93=27
3) x=40
angleTBA=180
TBC+Y+OBA=180
108+Y+40=180
148+Y=180
Y=180-148
Y=32
z+Y+angle C=180
z+32+32=180
z=180-62
z=118
3)30+57+angle0=180
angleAOC=180_87
angleAOC=93
and
I triangle oAB OA=OB
Angle OAB=OBA
angle BOA=120
BOA-AOC=BOC
120-93=27
3) x=40
angleTBA=180
TBC+Y+OBA=180
108+Y+40=180
148+Y=180
Y=180-148
Y=32
z+Y+angle C=180
z+32+32=180
z=180-62
z=118
aravinda67:
but the 2nd answer is not 80 it's 50
they asked to find angle a not angle o
sorry bro
180=80+2x
2x=100
x=50
correct bro
sorry i not read properly
I'm not a boy
I'm a girl
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