Question

please answer all the questions​

Answer 1

Step-by-step explanation:

In rectangle opposite sides are not equal

so,base of the triangle is 24m

Answer 2

Answer:

Question no. 1

$answer$

So, Area of the Quadrilateral ABCD=936 cm^{2}ABCD=936cm^2

Step-by-step explanation:

Given;

For a quadrilateral ABCD

AB=28cm , BC=26 cm ,CD=50 cm , DA=40 cm and diagonal AC=30

From figure,

By Heron's formula;

Area of triangle ABC=

√S (s-a) (s-b) (s-c) so where

$s = \binom{a + b + c}{2}$

SO ,

S= √42 (42-28) (42-26) (42-30)

$area \: of \: abc = {336}^{2}$

Similarly

By Heron's Formula

Area of ∆ ADC=

√S (s-a) (s-b) (s-c) where

$s = \binom{a + b + c}{2}$

SO,

S= 40+50+30/2= 60

S=60

Now Area of ADC

√60 (60-40) (60-50) (60-30)

Area of ∆ ADC=

$600 {cm}^{2}$

Area of Quadrilateral ABCD=

${300 + 600cm}^{2} = 936 {cm}^{2}$

Area of Quadrilateral ABCD=

$936 {cm}^{2}$

Thanks