please answer anyone of the parts
Answers
Step-by-step explanation:
Solutions :-
i)
Given nth term of the series = 3n+1
Put n= 1 then
=3(1)+1
= 3+1
=4
Put n=2 then
= 3(2)+1
= 6+1
= 7
Put n=3 then
= 3(3)+1
= 9+1
= 10
Put n= 4 then
= 3(4)+1
= 12+1
= 13
The first four terms are 4,7,10,13
ii)
Given nth term of the series = (2n-1)/(n+1)
Put n= 1 then
=[2(1)-1]/(1+1)
=(2-1)/(1+1)
=1/2
Put n=2 then
= [2(2)-1]/(2+1)
=(4-1)/(2+1)
=3/3
= 1
Put n=3 then
=[2(3)-1]/(3+1)
=(6-1)/(3+1)
=5/4
Put n= 4 then
= [2(4)-1]/(4+1)
= (8-1)/5
= 7/5
The first four terms are 1/2,1,5/4,7/5
iii)
Given nth term of the series = n²+1
Put n= 1 then
=1²+1
= 1+1
=2
Put n=2 then
= 2²+1
= 4+1
= 5
Put n=3 then
= 3²+1
= 9+1
= 10
Put n= 4 then
= 4²+1
= 16+1
= 17
The first four terms are 2,5,10,17
iv)
Given nth term of the series = 1/n²
Put n= 1 then
=1/1²
= 1/1
=1
Put n=2 then
=1/2²
= 1/4
Put n=3 then
= 1/3²
= 1/9
Put n= 4 then
= 1/4²
= 1/16
The first four terms are 1,1/4,1/9,1/16
v)
Given nth term of the series = 2n-3
Put n= 1 then
=2(1)-3
= 2-3
=-1
Put n=2 then
= 2(2)-3
= 4-3
= 1
Put n=3 then
= 2(3)-3
= 6-3
= 3
Put n= 4 then
= 2(4)-3
= 8-3
= 5
The first four terms are -1,1,3,5
vi)
Given nth term of the series =(n+1)²/n
Put n= 1 then
=(1+1)²/1
= 2²
=4
Put n=2 then
= (2+1)²/2
= 3²/2
= 9/2
Put n=3 then
= (3+1)²/3
= 4²/3
= 16/3
Put n= 4 then
= (4+1)²/4
= 5²/4
= 25/4
The first four terms are 4,9/2,16/3,25/4