Question

Please answer as fast as possible- Find four different solutions for 2x+3y = 6

Answer 1

Let x = 0

⇒ 2(0) + 3y = 6

⇒ 3y = 6

⇒ y = 2

Let x = 1

⇒ 2 + 3y = 6

⇒ 3y = 4

⇒ y = 4/3

Let x = 2

⇒ 4 + 3y = 6

⇒ 3y = 2

⇒ y = 2/3

Let x = 3

⇒ 6 + 3y = 6

⇒ 3y = 0

⇒ y = 0

So, the four solution are :-

1) x = 0

y = 2

2) x = 1

y = 4/3

3) x = 2

y = 2/3

4) x = 3

y = 0

Answer 2

Answer:

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