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the third angle of a triangle is the same size as the first. the second angle is 4 times the third. find the measure of the angles
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let the first angle be X
second angle be 4X
third angle be X
then X+X+4X=180
6X=180
X=180÷6
X=30
so first angle and third angle =30
third angle=30×4=120
second angle be 4X
third angle be X
then X+X+4X=180
6X=180
X=180÷6
X=30
so first angle and third angle =30
third angle=30×4=120
Answered by
0
#ANSWER#
Given the third angle of a triangle is the same size as the first.
The second angle is 4 times the third.
Let the first angle be x
Then the third angle will be x (given that 3rd angle=1st angle)
so the second angle be 4x
Forming the equation according to the question
we have
x + 4x + x = 180°( Sum of all angles of interior angles of a triangle is 180°)
6x = 180°
x = (180/6)°
x = 30°
So the first angle= 30°
Second angle = 4x = 4× 30 = 120°
Third angle = First angle = x = 30°
Thank you
@Be Brainly
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