Question

please answer asap need to be answered by wednesday morning Calculate the pH of 0.36M Ca(OH)2

Answer 1

Answer: pH of solution will be 13.8

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration and pOH is calculated by taking negative logarithm of hydroxide ion concentration.

$Ca(OH)_2\rightarrow Ca^{2+}+2OH^-$

1 mole of $Ca(OH)_2$ produces 2 moles of $OH^-$

Thus 0.36 moles of $Ca(OH)_2$ will produce $2\times 0.36=0.72$ moles of $OH^-$

$pOH=-log{OH^-}$

$pOH=-log{0.72}=0.14$

$pH+pOH=14$

$pH=14-0.14=13.8$

Thus pH of solution will be 13.8