Question

please answer both...... it's urgent please​

Answer 1

Answer:

1. perimeter of each square is (4×a) so,

first square perimeter is 64 and second is 28

and third square is 20

so,the total answer should be sum of

all the perimeters of the three squares

so it would be 122*

Answer 2

Step-by-step explanation:

1) Perimeter of the square A=4×side

=>4×16=64 units

Perimeter of the square B=3×7=21 units

remaining part is =16-7=9 units

perimeter of the square C=3×5=15units

Remaining part=7-5=2 units

Total perimeter=64+21+15+9+2=111 units

2)From the given figure

Angle A=Angle B=>AC=BC

Let Bc=AC=X

now the perimeter=AB+BC+AC=16

=>6+X+x=16

=>2X+6=16

=>2x=16-6

=>2x=10

=>x=10/2

=>x=5

AC=BC=5units