Question

please answer by solving
in figure 8 abcd is a rhombus whose diagonal ac and bd intersect at o if oaB:oba =3:2 find the measure of the all angle of cod​

Answer 1

2458558578688686685876787

Answer 2

Answer:

Given: ABCD is a rhombus, angle OAB:angle OBA = 3:2

to find : angles of ∆OAB

proof - we know that diagnols of a rhombus are perpendicular to each other , angle AOB=90°

Let angle OAB=2x, angle OBA=3x

sum of angles of a triangle is 180°

So,

In ∆ OAB,

2x+3x+90°=180°

5x=90°

x=12°

angle OAB = 2x = 2 × 12 = 36°

angle OBA = 3x = 3× 12 = 54°

Hence, the values of angles of ∆OAB are 90°, 36°,54°.